我想在sql 2008上写一个查询,报告所有可以访问特定数据库的用户,或数据库中的对象,如表、视图和存储过程,无论是直接访问还是由于角色等。 这个报告将被用于安全审计的目的。 不确定是否有人有一个完全适合我的需求的查询,但希望能给我一个好的开始。无论是sql 2008, 2005还是2000都可以,我可以根据需要进行转换。
这是我根据Andomar的建议,第一次尝试做一个查询。 这个查询的目的是提供一个用户的权限列表,这些权限可以直接应用于用户账户,也可以通过用户的 用户拥有的角色。
/*
Security Audit Report
1) List all access provisioned to a sql user or windows user/group directly
2) List all access provisioned to a sql user or windows user/group through a database or application role
3) List all access provisioned to the public role
Columns Returned:
UserName : SQL or Windows/Active Directory user account. This could also be an Active Directory group.
UserType : Value will be either 'SQL User' or 'Windows User'. This reflects the type of user defined for the
SQL Server user account.
DatabaseUserName: Name of the associated user as defined in the database user account. The database user may not be the
same as the server user.
Role : The role name. This will be null if the associated permissions to the object are defined at directly
on the user account, otherwise this will be the name of the role that the user is a member of.
PermissionType : Type of permissions the user/role has on an object. Examples could include CONNECT, EXECUTE, SELECT
DELETE, INSERT, ALTER, CONTROL, TAKE OWNERSHIP, VIEW DEFINITION, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
PermissionState : Reflects the state of the permission type, examples could include GRANT, DENY, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
ObjectType : Type of object the user/role is assigned permissions on. Examples could include USER_TABLE,
SQL_SCALAR_FUNCTION, SQL_INLINE_TABLE_VALUED_FUNCTION, SQL_STORED_PROCEDURE, VIEW, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
ObjectName : Name of the object that the user/role is assigned permissions on.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
ColumnName : Name of the column of the object that the user/role is assigned permissions on. This value
is only populated if the object is a table, view or a table value function.
*/
--List all access provisioned to a sql user or windows user/group directly
SELECT
[UserName] = CASE princ.[type]
WHEN 'S' THEN princ.[name]
WHEN 'U' THEN ulogin.[name] COLLATE Latin1_General_CI_AI
END,
[UserType] = CASE princ.[type]
WHEN 'S' THEN 'SQL User'
WHEN 'U' THEN 'Windows User'
END,
[DatabaseUserName] = princ.[name],
[Role] = null,
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = obj.type_desc,--perm.[class_desc],
[ObjectName] = OBJECT_NAME(perm.major_id),
[ColumnName] = col.[name]
FROM
--database user
sys.database_principals princ
LEFT JOIN
--Login accounts
sys.login_token ulogin on princ.[sid] = ulogin.[sid]
LEFT JOIN
--Permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = princ.[principal_id]
LEFT JOIN
--Table columns
sys.columns col ON col.[object_id] = perm.major_id
AND col.[column_id] = perm.[minor_id]
LEFT JOIN
sys.objects obj ON perm.[major_id] = obj.[object_id]
WHERE
princ.[type] in ('S','U')
UNION
--List all access provisioned to a sql user or windows user/group through a database or application role
SELECT
[UserName] = CASE memberprinc.[type]
WHEN 'S' THEN memberprinc.[name]
WHEN 'U' THEN ulogin.[name] COLLATE Latin1_General_CI_AI
END,
[UserType] = CASE memberprinc.[type]
WHEN 'S' THEN 'SQL User'
WHEN 'U' THEN 'Windows User'
END,
[DatabaseUserName] = memberprinc.[name],
[Role] = roleprinc.[name],
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = obj.type_desc,--perm.[class_desc],
[ObjectName] = OBJECT_NAME(perm.major_id),
[ColumnName] = col.[name]
FROM
--Role/member associations
sys.database_role_members members
JOIN
--Roles
sys.database_principals roleprinc ON roleprinc.[principal_id] = members.[role_principal_id]
JOIN
--Role members (database users)
sys.database_principals memberprinc ON memberprinc.[principal_id] = members.[member_principal_id]
LEFT JOIN
--Login accounts
sys.login_token ulogin on memberprinc.[sid] = ulogin.[sid]
LEFT JOIN
--Permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN
--Table columns
sys.columns col on col.[object_id] = perm.major_id
AND col.[column_id] = perm.[minor_id]
LEFT JOIN
sys.objects obj ON perm.[major_id] = obj.[object_id]
UNION
--List all access provisioned to the public role, which everyone gets by default
SELECT
[UserName] = '{All Users}',
[UserType] = '{All Users}',
[DatabaseUserName] = '{All Users}',
[Role] = roleprinc.[name],
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = obj.type_desc,--perm.[class_desc],
[ObjectName] = OBJECT_NAME(perm.major_id),
[ColumnName] = col.[name]
FROM
--Roles
sys.database_principals roleprinc
LEFT JOIN
--Role permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN
--Table columns
sys.columns col on col.[object_id] = perm.major_id
AND col.[column_id] = perm.[minor_id]
JOIN
--All objects
sys.objects obj ON obj.[object_id] = perm.[major_id]
WHERE
--Only roles
roleprinc.[type] = 'R' AND
--Only public role
roleprinc.[name] = 'public' AND
--Only objects of ours, not the MS objects
obj.is_ms_shipped = 0
ORDER BY
princ.[Name],
OBJECT_NAME(perm.major_id),
col.[name],
perm.[permission_name],
perm.[state_desc],
obj.type_desc--perm.[class_desc]
从SQL Server 2005开始,你可以使用系统视图来实现这一点。 例如,这个查询列出了一个数据库中的所有用户,以及他们的权限。
select princ.name
, princ.type_desc
, perm.permission_name
, perm.state_desc
, perm.class_desc
, object_name(perm.major_id)
from sys.database_principals princ
left join
sys.database_permissions perm
on perm.grantee_principal_id = princ.principal_id
请注意,一个用户也可以通过一个角色拥有权利。 例如,db_data_reader
角色授予大多数对象的select
权利。
我不能对已接受的答案发表评论,所以我将在这里补充一些评论。
sys.objects
表只包含模式范围的对象。因此,要获得更高级别的对象(即我们案例中的模式)的信息,你需要使用sys.schemas
表。[ObjectType]
,最好只对OBJECT_OR_COLUMN
权限类别使用obj.type_desc
。对于所有其他情况使用perm.[class_desc]
.IMPERSONATE', 这种查询方式不能很好地处理.要获得关于冒名顶替的信息,应该
LEFT JOIN与
sys.database_principals在
perm.main_id = imp.principal_id`上。sys.login_token
替换为sys.server_principals
,因为它也会显示SQL登录,而不仅仅是Windows登录。'G'
,以允许Windows组。sys
和INFORMATION_SCHEMA
,因为这些用户只用于服务。我将发布第一段带有所有建议修复的脚本,其他部分也应该被修改。
SELECT
[UserName] = ulogin.[name],
[UserType] = CASE princ.[type]
WHEN 'S' THEN 'SQL User'
WHEN 'U' THEN 'Windows User'
WHEN 'G' THEN 'Windows Group'
END,
[DatabaseUserName] = princ.[name],
[Role] = null,
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = CASE perm.[class]
WHEN 1 THEN obj.type_desc -- Schema-contained objects
ELSE perm.[class_desc] -- Higher-level objects
END,
[ObjectName] = CASE perm.[class]
WHEN 1 THEN OBJECT_NAME(perm.major_id) -- General objects
WHEN 3 THEN schem.[name] -- Schemas
WHEN 4 THEN imp.[name] -- Impersonations
END,
[ColumnName] = col.[name]
FROM
--database user
sys.database_principals princ
LEFT JOIN
--Login accounts
sys.server_principals ulogin on princ.[sid] = ulogin.[sid]
LEFT JOIN
--Permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = princ.[principal_id]
LEFT JOIN
--Table columns
sys.columns col ON col.[object_id] = perm.major_id
AND col.[column_id] = perm.[minor_id]
LEFT JOIN
sys.objects obj ON perm.[major_id] = obj.[object_id]
LEFT JOIN
sys.schemas schem ON schem.[schema_id] = perm.[major_id]
LEFT JOIN
sys.database_principals imp ON imp.[principal_id] = perm.[major_id]
WHERE
princ.[type] IN ('S','U','G') AND
-- No need for these system accounts
princ.[name] NOT IN ('sys', 'INFORMATION_SCHEMA')